Question

15. Calculați compoziţia procentuală de masă pentru următoarele substanţe: a. NaOH b. CUSO4 C. NH_NO3 d. MgCO3
AJUTOR!!!! ​

Answer 1

Răspuns:

a) MNaOH=23+16+1=40g/mol

40gNaOH.................23gNa...............16gO................1gH

100gNaOH...................xgNa..............ygO........ .......zgH

x= 100×23/40= calculeaza

y=100×16/40= calculeaza

z= 100×1/40= calculeaza

b)

MCuSO4=64+32+4×16=160g/mol

160g CuSO4...........64gCu................32gS............64gO

100CuSO4.................xgCu.................ygS...................zgO

x=100×64/160= caluleaza

y=100×32/160= calculeaza

z= 100×64/160= calculeaza

c)

MNH4NO3=14+4×1+14+3×16=80g/mol

80gNH4NO3.............28gN..............4gH........48gO

100NH4NO3............xgN.................ygH..............zgO

x=100×28/90= calculeaza

y=100×4/80= calculeaza

z=100×48/8= calculeaza

d)

MMgCO3=24+12+3×16=84g/mol

84g MgCO3...................24gMg.............12gC..................48gO

100gMgCO3...................xgMg..................ygC..................zgO

x=100×24/84= calculeaza

y=100×12/84= calculeaza

z=100×48/84= calculeaza

Explicație: