Question

15. Rezolvaţi în mulţimea numerelor întregi ecuațiile:
a) 2 - (x + 1) = -7(x + 3) + 3(3x - 5) – 5;
b) -3 · (3x + 1) + 14 = 3(7x – 3) - 10;
c) 14 + 2 - [3 – 2(x – 3)] : 2 = 37;
d) 4-{6-[-3 + (-3) + (-5 – x) – 7] - 9} = 1;
e) 5 · (7x - 1)° + 2(x + 1) =-7(x + 3) + 3(3x – 5) + 43.​

Answer 1

Răspuns:

a) 2-(x+1)=-7(x+3)+3(3x-5)-5 =

2-x-1=-7x-21+9x-15-5=

1-x=2x-41=

-x-2x=-41-1=

-3x=-42=

x=14

b)-3*(3x+1)+14=3(7x-3)-10=

-9x-3+14=21x-9-10=

-9x+11=21x-19=

-9x-21x+-19-11

-30x=-30

x=1

c)a sati scriu de la primu egal

16-(3-2x+6)impartit2=37

16-(9-2x)impartit2=37

16-(9-2x)/2=37

32-(9-2x)=74

32-9+2x=74

23+2x=74

2x=74-23

2x=51

x=51/2 sau 25,5

d)

4-[6-(-3-3-5-x-7)-9]=1

4-[6-(-18-x)-9)=1

4-(6+18+x-9)=1

4-(15+x)=1

4-15-x=1

-11-x=1

-x=1+11

-x+12

x=-12

e)

35x-5+2x+2=-7x-21+9x-15+43

37x-3+2x+7

37x-2x=3+7

35x=10

x=2/7 sau 0,28

Explicație pas cu pas: