Question

-15 supra18-11supra12 + 3,(2) - 16supra6

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Answer 1

Răspuns:

-15/18 = -5/6

3,(2) = 3 întregi 2/9 = 20/9

16/6 = 8/3

-5/6 - 11/12 + 20/9 - 8/3 =

Numitor comun :

6=2×3

12=2^2 × 3

9=3^2

3=3×1

cmmmc = 2^2 × 3^2 = 36

(-30-33+80-96)/36 =

-68/36 =

-34/18=

-17/9