Question

151:n=3rest1 n = ?

0+[(1+2x3):c+5]:6=1

Answer 1

1) 151:n=3 rest 1⇒151=3x+1
3x=151-1
3x=150
x=150:3=50
2) 0+[(1+2*3):c+5]:6=1
[(1+6):c+5]:6=1-0=1
7:c+5=1*6=6
7:c=6-5=1
c=7:1=7

Answer 2

151:n=3rest1
n=(151-1):3
n=150:3
n=50
 
0+[(1+2x3):c+5]:6=1
0+[(1+6):c+5]:6=1
0+(7:c+5):6=1
0+(7:c+5)=1x6
0+(7:c+5)=6
7:c+5=6
7:c=6-5
7:c=1
c=7:1
c=7