Question

√16[2]+12[2] (totul sub radical) -√961

[2] = la puterea doua.;
rezolvarea completa.

Answer 1

√(16²+12²)-√961=
=√(256+144)-31=
=√400-31=
=20-31=-11

Answer 2

$\sqrt{16^2+12^2} - \sqrt{961} = \sqrt{256+144} -31= \sqrt{400} -31=20-31=\boxed{-11}$