Question

(16^4x8^5:4^15+2^0+2^2)x4-5^2

^=ridicarea la putere

Answer 1

Răspuns:

Explicație pas cu pas:

( 16^4 × 8^5 : 4^15 + 2^0 + 2^2 ) × 4 - 5^2 =

[ ( 2^4 )^4 × ( 2^3 )^5 : ( 2^2 )^15 + 1 + 4 ] × 4 - 25 =

( 2^16 × 2^15 : 2^30 + 1 + 4 ] × 4 - 25 =

[ 2^( 16 + 15 ) : 2^30 + 5 ] × 4 - 25 =

( 2^31 : 2^30 + 5 ) × 4 - 25 =

( 2^1 + 5 ) × 4 - 25 =

( 2 + 5 ) × 4 - 25 =

7 × 4 - 25 =

28 - 25 = 3

Answer 2

$( {16}^{4} \times {8}^{5} \div {4}^{15} + 2 {}^{0} + {2}^{2} ) \times 4 - {5}^{2}$

$( {4}^{8} \times {8}^{5} \div 4 {}^{15} + {2}^{0} + 2 {}^{2} ) \times 4 - {5}^{2}$

$( {4}^{8} \times {2}^{15} \div 4 {}^{15} + {2}^{0} + {2}^{2} ) \times 4 - {5}^{2}$

$( {4}^{8} \times {2}^{15} \div 2 {}^{30} + {2}^{0} + 2 {}^{2} ) \times 4 - {5}^{2}$

$( {4}^{8} \times {2}^{15} \div {2}^{30} + 1 + 2 {}^{2} ) \times 4 - {5}^{2}$

$( {4}^{8} \times {2}^{15} \div {2}^{30} + 1 + 4 ) \times 4 - {5}^{2}$

$( {2}^{16} \times {2}^{15} \div {2}^{30} + 1 + 4) \times 4 - 25$

$(2 {}^{16 + 15 - 30} + 1 + 4) \times 4 - 25$

$(2 {}^{1} + 1 + 4) \times 4 - 25$

$(2 + 1 + 4) \times 4 - 25$

$(3 + 4) \times 4 - 25$

$7 \times 4 - 25$

$28 - 25$

$3$