Question

16) Din şirul de fracții:

8⁶/2²⁰

3³/2⁵

5⁴/25²

2²×2³/5²

1²⁰²²/2022⁰

(4³)²/2¹⁴

scrie fractiile:

a) subunitare

b) echiunitare

c) supraunitare​

Answer 1

Explicație pas cu pas:

$\dfrac{ {8}^{6} }{ {2}^{20} } = \dfrac{ {( {2}^{3} )}^{6} }{ {2}^{20} } = \dfrac{ {2}^{18} }{ {2}^{20} } < 1$

$\dfrac{ {3}^{3} }{ {2}^{5} } = \dfrac{27}{32} < 1$

$\dfrac{ {5}^{4} }{ {25}^{2} } = \dfrac{ {5}^{4} }{ {( {5}^{2} )}^{2} } = \dfrac{ {5}^{4} }{ {5}^{4} } = 1$

$\dfrac{ {2}^{2} \times {2}^{3} }{ {5}^{2} } = \dfrac{4 \times 8}{25} = \dfrac{32}{25} > 1$

$\dfrac{ {1}^{2022} }{ {2022}^{0} } = \dfrac{1}{1} = 1$

$\dfrac{ {( {4}^{3} )}^{2} }{ {2}^{14} } = \dfrac{{4}^{6}}{ {2}^{14} } = \dfrac{{( {2}^{2} )}^{6}}{ {2}^{14} } = \dfrac{{2}^{12}}{ {2}^{14} } < 1$

a) subunitare:

$\dfrac{ {8}^{6} }{ {2}^{20} } \ ; \ \dfrac{ {3}^{3} }{ {2}^{5} } \ ; \ \dfrac{ {( {4}^{3} )}^{2} }{ {2}^{14} }$

b) echiunitare:

$\dfrac{ {5}^{4} }{ {25}^{2} } \ ; \ \dfrac{ {1}^{2022} }{ {2022}^{0} }$

c) supraunitare:

$\dfrac{ {2}^{2} \times {2}^{3} }{ {5}^{2} }$