Question

17-4x[6-3x(m:4-15)]+95=100. (m tre sa iasă 64
1000-[77+5x(4xr+68)]=63(r tre sa iasă 26
1154+7x[1008-6x(9-6x u:3)]=8000(i tre sa ias 2

22-[59+2x(5+t x 8)-1]:9=2 (t tre sa iasă 7

Answer 1

1000-[77+5x(4xr+68)]=63
77+5x(4xr+68)=1000-63
77+5x(4xr+68)=937
5x(4xr+68)=937-77
5x(4xr+68)=860
4xr+68=860:5
4xr+68=172
4xr=172-68
4xr=104
r=104:4
r=26

1154+7x[1008-6x(9-6x u:3)]=8000
7x[1008-6x(9-6x u:3)]=8000-1154
7x[1008-6x(9-6x u:3)]=6846
1008-6x(9-6x u:3)=6846:7
1008-6x(9-6x u:3)=978
6x(9-6x u:3)=1008-978
6x(9-6x u:3)=30
9-6x u:3=30:6
9-6x u:3=5
6x u:3=9-5
6x u:3=4
6:3xu=4
2xu=4
u=4:2
u=2

22-[59+2x(5+t x 8)-1]:9=2 
[59+2x(5+t x 8)-1]:9=22-2
[59+2x(5+t x 8)-1]:9=20
59+2x(5+t x 8)-1=20x9
59+2x(5+t x 8)-1=180
2x(5+t x 8)-1=180-59
2x(5+t x 8)-1=121
2x(5+t x 8)-1=121+1
2x(5+t x 8)=122
5+t x 8=122:2
5+t x 8=61
t x 8=61-5
t x 8=56
t=56:8
t=7

17-4x[6-3x(m:4-15)]+95=100
17-4x[6-3x(m:4-15)]=100-95
17-4x[6-3x(m:4-15)]=5
4x[6-3x(m:4-15)]=17-5
4x[6-3x(m:4-15)]=12
6-3x(m:4-15)=12:4
6-3x(m:4-15)=3
3x(m:4-15)=6-3
m:4-15=3:3
m:4-15=1
m:4=1+15
m:4=16
m=16x4
m=64