Question

17/5:(11/6 la puterea 2-27/9)

Answer 1

$\frac{\frac{17}{5}}{\left(\frac{11}{6}\right)^2-\frac{27}{9}}$

$=\frac{17}{5\left(\left(\frac{11}{6}\right)^2-\frac{27}{9}\right)}$

$=\frac{17}{5\left(\frac{11^2}{6^2}-\frac{27}{9}\right)}$

$=\frac{17}{5\left(\frac{11^2}{6^2}-3\right)}$

$\frac{11^2}{6^2}$

$=\frac{17}{5\left(\frac{121}{36}-3\right)}$

$=\frac{17}{5\cdot \frac{13}{36}}$

$=\frac{17}{\frac{65}{36}}$

$=\frac{17\cdot \:36}{65}$

$=\frac{612}{65}$

Sper că te-am ajutat!

Succes!