Question

17 . Calculati :
a) (4+3) la putere 3 - (4-3) la putere 10 =
b) ( 10 la putere 3 - 125* 2 la putere 3 ) : 123 la putere 123 =
c) [(10 la putere 3 : 5 la putere 2 : 8 + 3 la putere 2 * 5 la putere 2 ):3 la putere 0 ] *2la putere 2 la putere 0 =
d){[(12 la putere 2 si 5 la p[utere 2 ):13] la putere2 - 2 la putere 7 - 2 la putere 0}:2 la putere3=

Answer 1

a) 7 la 3 -1la10=342
b)(10la3-125*2la3):123la123=(1000-1000):123la 123=0
c)(1000:25:8+9*25):1)*1=350
d) nu intele cum asta 12 la putere 2 si 5 la putere 2, ce semn intre ele

Answer 2

a) (4+3)³ - (4-3)¹⁰ =7³-1=343-1=342
b) ( 10 ³- 125* 2³ ) : 123¹²³= ( 10 ³- 5³* 2³ ): 123¹²³=(10³-10³):123¹²³= =0:123¹²³=0
c) [(10³ : 5² : 8 + 3² * 5² ):3⁰] *2²^0= [(5 + 3²*5² ): 1] *2¹=
= [5*(1+3²*5):1] :2= [5*(1+9*5):1] :2=(5*46):2= 112

d){[(12 ²+ 5²  ):13] ² - 2⁷ - 2⁰}:2³= {[(144+25  ):13] ² - 128- 1}: 8=
=[ (169:13)²-128-1]: 8=(13²-128-1):8 =(169-128-1) : 8=40 : 8=5