Question

17. Calculaţi:
I a VII-a
a) 13(4 + 16)-(V12 - V18)+(127 +276): 15-(18+3);
(V150 – 3/10): V2 + ( 145 - 5) - 175; c) (154 - v24): 13-(V160 – 40): 15.
b)​

Answer 1

Explicație pas cu pas:

$a) \: 13 \times 20 - (2 \sqrt{3} - 3 \sqrt{2} ) + 403 \div 15 - 21 = 260 - 2 \sqrt{3} + 3 \sqrt{2} + 26.86 - 21 = 212.14 - 2 \sqrt{3} + 3 \sqrt{2}$

$b) \: (\sqrt{150} - \frac{3}{10} ) \div \sqrt{2} + 140 - 175 = (5 \sqrt{6} - \frac{3}{10} ) \div \sqrt{2} - 35 = ( \frac{50 \sqrt{6 } - 3}{10} ) \div \sqrt{2} - 35 = \frac{100 \sqrt{3} - 3 \sqrt{2} }{20} - 35 = \frac{100 \sqrt{3} - 3 \sqrt{2} - 700 }{20}$

$(154 - \sqrt{24} ) \div 13 - ( \sqrt{160} - 40) \div 15 = (154 - 2 \sqrt{6} ) \div 13 - (4 \sqrt{10} - 40) \div 15 = \frac{154 - 2 \sqrt{6} }{13} - \frac{4 \sqrt{10} - 40 }{15} = \frac{2830 - 30 \sqrt{6} - 52 \sqrt{10} }{195}$