Question

(17 supra 16 -1 supra 128+3supra 64)*256 supra 47 =
DAU COROANA!!!!-

Answer 1

( 17 / 16 - 1 / 128 + 3 / 64 ) × 256 / 47 = 6

→ aflam cmmmc al numitorilor ( 16, 128 si 64 )

16 = 2⁴

128 = 2⁷

64 = 2⁶

_________

cmmmc al numitorilor ( 16; 128 si 64 ) = 2⁷ = 128

→ aducem fractiile la acelasi numitor 128, amplificand prima fractie cu 8, iar fractia 3 / 64 cu 2 :

= ( 136/ 128 - 1 / 128 + 6 / 128 ) × 256 / 47 =

= 141 / 128 × 256 / 47 =

= 141 / 47 × 256 / 128 =

= 3 × 2 =

= 6

Answer 2

$( \frac{17}{16} - \frac{1}{128} + \frac{3}{64}) : \frac{256}{47} = \\ \\ \frac{141}{128} \times \frac{256}{47} = \frac{141 \times 256}{128 \times 47} = \frac{36096}{6016} = 6$