Question

(18√12+12√18):6√6-3(√2+1)

Answer 1

primadata descopui numerele de sub radicali adica
12=2×2×3⇒√12=√4×3=2√3
18=2×3×3⇒√18=√9×2=3√2
√6=√6
√2=√2
(18×2√3+12×3√2):6√6-3(√2+1)=
=(36√3+36√2):6√6-3√2+3
=36(√3+√2):6√6-3√2+3(operez 36:6√6=√6)
=√6(√3+√2)-3√2+3
=√18+√12-3√2+3
=3√2+2√3-3√2+3
=2√3+3