Question

18. Câte numere de forma abcd verifică relația abc = d0+c la puterea b?
A. 4
B. 5
C. 6
D. 8


VA ROGGG DAU FUNDA​

Answer 1

Răspuns: 6 numere

$\color{DarkBlue} \boxed{\boxed{\bf \overline{abcd}~\in \bigg\{5928, 2531, 5452, 1351, 2362,7391 \bigg\} }}$

Explicație pas cu pas:                                                                              

$\bf \overline{abcd} = ???$

$\bf a,b,c,d - cifre$

$\bf a\neq 0$

$\bf \overline{abc}= \overline{d0}+c^{b}$

$\bf \overline{abcd}= \overline{abc}\cdot 10+d$

$\bf Inlocuim~pe~ \overline{abc}~si~vom~avea: \overline{abcd}= (\overline{d0}+c^{b})\cdot 10+d$

$\bf \overline{abcd}= \overline{d00}+10c^{b}+d$

$\text{\underline{\it Descompunem in baza 10}}$

$\bf 1000a +100b+10c+d=\overline{d00}+10c^{b}+d$

$\bf 1000a +100b+10c= \overline{d00}+10c^{b}+d-d$

$\bf 1000a +100b+10c= \overline{d00}+10c^{b}$

$\bf 1000a +100b+10c= 100d+10c^{b}~~\bigg|:10$

$\bf 100a +10b+c= 10d+c^{b}$

$\bf c^{b} =100a +10b+c- 10d$

$\bf c^{b} =100a +10\cdot(b-d) +c$

$\it~~~$

$\bf c^{b}~ va~ fi~ un~ nr.~ format~ din~ 3~ cifre~care~adunat~ cu~\overline{d0} = nr.~ de~ 4~ cifre$$\it~~~$$\text{\bf De acum dai valori lui c si b a.i.}\bf~c^{b}~sa~fie~un~nr. ~de~ 3~ cifre$$\text{\bf Nu voi lua toate cazurile care nu convin ca e foarte mult de scris}$

$\it~~~$          

$\bf \star~~ Daca~ c^{b} = 2^{8} = 256\implies 256=100a +80+2-10d$

$\bf \implies 174 = 100a -10d \implies 87 = 50-5d~~Nu ~convine$   $\it~~~~$

$\bf \star~~ Daca~ c^{b} = 2^{9} = 512\implies 512=100a +90+2-10d$

$\bf 420=100a -10d\implies d = 10a-42\implies a= 5; d =8;c =2;b=9$

$\boxed{\bf \overline{abcd} = 5928~~solutie}$

$\it~~~$

$\bf \star~~ Daca~ c^{b} = 3^{5} = 243\implies 243=100a +50+3-10d$

$\bf \implies 190=100a -10d \implies d = 10a- 19\implies a =2; b=5;c=3;d=1$

$\boxed{\bf \overline{abcd} = 2531~~solutie}$

$\it~~~~~~~~~~~$

$\bf \star~~ Daca~ c^{b} = 5^{3} = 125\implies 125=100a +30+5-10d$

$\bf\implies 90=100a -10d\implies d=10-9\implies a=1;b=3;c=5;d=1$

$\boxed{\bf \overline{abcd} = 1351~~solutie}$

$\it~~~$

$\bf \star~~ Daca~ c^{b} = 5^{4} = 625\implies 125=100a +40+5-10d\implies$

$\bf\implies 580=100a -10d\implies d=10a-58\implies a=5;b=4;c=5;d=2$

$\boxed{\bf \overline{abcd} = 5452~~solutie}$

$\it~~~~$

$\bf \star~~ Daca~ c^{b} = 6^{3} = 216\implies 216=100a +30+6-10d\implies$

$\bf \implies 180=100a -10d\implies d = 10a -18\implies a=2;b=3;c=6;d=2$

$\boxed{\bf \overline{abcd} = 2362~~solutie}$

$\it~~$

$\bf \star~~ Daca~ c^{b} = 9^{3} = 7292\implies 729=100a +30+9-10d \implies$

$\bf \implies 690=100a -10d\implies d = 10a -69\implies a=7;b=3;c=9;d=1$

$\boxed{\bf \overline{abcd} = 7391~~solutie}$

$\text{\bf Din cazurile analizate avem:}$

$\color{DarkBlue} \boxed{\boxed{~\bf \overline{abcd}~\in \bigg\{5928, 2531, 5452, 1351, 2362,7391 \bigg\} }}$

$\text{\bf PS: Daca esti pe telefon te rog sa glisezi spre dreapta pentru a vedea}$

$\text{\bf rezolvarea completa}$

==pav38==