Question

18(x+2)^2=(6+3V2)^2
​.

Answer 1

Răspuns:

Explicație pas cu pas:

$18(x+2)^2=(6+3\sqrt{2} )^2 \ \ \Big|:18$

$(x+2)^2=\dfrac{(6+3\sqrt{2} )^2}{(3\sqrt{2} )^{2} }$

$(x+2)^2 = \bigg(\dfrac{6}{3\sqrt{2}}+1\bigg)^{2} \iff (x+2)^2 = (\sqrt{2} + 1)^2$

$|x + 2| = \sqrt{2} + 1$

$x+2 = -(\sqrt{2} + 1) \iff x_{1} = - \sqrt{2} - 3$

$x+2 = \sqrt{2} + 1 \iff x_{2} = \sqrt{2} - 1$