Question

[19supra6+(1 1supra3)la puterea9:(1,(3))la puterea8]•(0,02)la puterea3. Va rog ajutatima, este urgent.

Answer 1

[19/6+(1 1/3)⁹:(1,(3))⁸]•(0,02)³=
={19/6+(4/3)⁹:[(13-1)/9]⁸}•(2/100)³=
=[19/6+(4/3)⁹:(12/9)⁸]•(1/50)³=
=[19/6+(4/3)⁹:(4/3)⁸]•(1/50)³=
=[19/6+(4/3)⁹•(3/4)⁸]•(1/50)³=
=(19/6+4/3)•(1/50)³=
=(19+8)/6•(1/50)³=
=27/6•(1/50)³=
=9/2•1/125000=
=9/250000=0,000036