Question

(1p) 2 Se consideră funcția f: {-1, 0, 2,4} -> {0, 1, 3, a), f(x)=x+1. Determinaţi numarul real a​

Answer 1

$\bf f(x) = x + 1$

$x = -1 \iff f(-1) = -1 + 1 = 0$

$x = 0 \iff f(0) = 0 + 1 = 1$

$x = 2 \iff f(2) = 2 + 1 = 3$

$x = 4 \iff f(4) = 4 + 1 = 5$

am obținut valorile: 0, 1, 3, 5

$f: \{-1, 0, 2,4\} \to \{0, 1, 3, 5\}$

$\{0,1,3,5\} = \{0,1,3,a\} \implies \bf a = 5$