Question

[1pe 2+0,5·1,1(6)]·0,(27)

Answer 1

[tex] [ \frac{1}{2}+ \frac{5}{10} * \frac{116-11}{90} ] * \frac{27}{99} = [ \frac{1}{2}+ \frac{5}{10} * \frac{105}{90} ] * \frac{27}{99} = [ \frac{1}{2}+ \frac{1}{2} * \frac{7}{6} ] * \frac{3}{11} =[/tex] =
[tex] [ \frac{1}{2}+ \frac{7}{12} ] * \frac{3}{11} = [ \frac{6}{12} + \frac{7}{12} ]* \frac{3}{11} = \frac{13}{12} * \frac{3}{11} = \frac{13}{44}[/tex]

Daca este ceva ce nu intelegi te rog sa imi spui.