Question

(1supra 6+ 7supra 9)•18supra 17+2 supra 3 •(1supra 7 -1supra 21

Answer 1

(1/6+7/9) × 18/17 +2/3 ×(1/7-1/21)=
=(3/18+14/18) × 18/17 +2/3 ×(3/21-1/21)=
=17/18 × 18/17 +2/3 × 2/21=
=1+4/63=63/63+4/63=67/63
67/63=1,(063492)

Answer 2

((1/6+7/9)*18)/17+(2(1/7-1/21))/3=((3/18+14/18)*18)/17+(2(1/7-1/21))/3=[((3+14)/18)*18]/17+(2(1/7-1/21))/3=((17/18)*18)/17+(2(1/7-1/21))/3=(17*18)/(18*17)+(2(1/7-1/21))/3=1+(2(1/7-1/21))/3=1+(2(2/21))/3=1+(4/21)/3=1+(4/21*3)=1+4/63=63/63+4/63=63+(4/63)=67/63 sau 1 intreg  si 4/63