Question

1supra radical 8-1supra radical 2 +radical 8 supra 8

Answer 1

$\frac{1}{ \sqrt{8} } - \frac{1}{ \sqrt{2} } + \frac{ \sqrt{8} }{8} = \\ \frac{1 \sqrt{8} }{8} - \frac{1 \sqrt{2}}{2} + \frac{ \sqrt{8} }{8}= \\1 \sqrt{8} - 4*4 + \sqrt{8}= 1 \sqrt{8} -16+ \sqrt{8}$