Question

1supra radical din 3+1+1supra3 minus radical din 3 minus 1 supra radical din 3​

Answer 1

${}^{ {}^{ \sqrt{3} - 1)} } \frac{1}{ \sqrt{3} + 1 } + {}^{ {}^{3 + \sqrt{3}) } } \frac{1}{ 3 - \sqrt{3} } - {}^{ {}^{ \sqrt{3}) } } \frac{1}{ \sqrt{3} } \\ \\ = \frac{ \sqrt{3} - 1 }{3 - 1} + \frac{3 + \sqrt{3} }{9 - 3} - \frac{ \sqrt{3} }{3} \\ \\ = {}^{ {}^{3)} } \frac{ \sqrt{3} - 1}{2} + \frac{3 + \sqrt{3} }{6} - {}^{ {}^{2)} } \frac{ \sqrt{3} }{3} \\ \\ = \frac{3 \sqrt{3} - 3 }{6} + \frac{3 + \sqrt{3} }{6} - \frac{2 \sqrt{3} }{6} \\ \\ = \frac{3 \sqrt{3} - 3 + 3 + \sqrt{3} - 2 \sqrt{3} }{6} \\ \\ = \frac{2 \sqrt{3} }{6} \\ \\ = \frac{ \sqrt{3} }{3}$