Question

-1supra4 x²y*2xy-1 supra2 x³y²-(-2 supra 27 x³y ridicat la puterea a 4: 1 supra 9 x²y)=

Answer 1

-(x³y²)/2-(x³y²)/2-(-2-9x³y⁴)/(27x²y)=
-(x³y²)/2-(x³y²)/2-(-2x³y⁴)/(3x²y)=
-(x³y²)/2-(x³y²)/2-(-2xy³)/3=
-(x³y²)/2-(x³y²)/2+(2xy³)/3=
(-3x³y²)/6-(3x³y²)/6+(4xy³)/6=
(-3x³y²-3x³y²+4xy³)/6=
(-6x³y²+4xy³)/6=
(2xy²(2y-3x²))/3

(2xy³)/3-x³y²=0
-1/3xy²(3x²-2y)=0
y²(3x²-2y)=0
3x²-2y=0⇒-2y=-3x²⇒y=3x²/2
y²=0⇒y=0