Question

2^0+2^1+2^2+2^3+...+2^2019+2^2020


Va rog repede

Answer 1

2^0+2^1+2^2+2^3+...+2^2019+2^2020=S ×/2

±2⁰+2+2²+2³+2⁴.+..+2²⁰²⁰+2²⁰²¹=2S

-2⁰+(2⁰+.. +2²⁰²⁰)+2²⁰²¹=2S

-2⁰+S+2²⁰²¹=2S

S=2²⁰²¹-1