Question

[2^0+2^1+3^14:(3×13^12)]^12:3^2 va rog sa ma ajutati!​

Answer 1

Răspuns:

= 4·6¹⁰

Explicație pas cu pas:

[2⁰+2¹+3¹⁴:(3·3¹²)]¹² :3² =

=[1+2+3¹⁴:3¹⁺¹²]¹² : 3² =

= (3+3¹⁴⁻¹³)¹² :3²  =

= (3+3)¹² : 3²  =

= 6¹² : 3² =

= (2·3)¹² : 3²  =

= 2¹² ·3¹²:3² =

= 2¹²·3¹²⁻² =

=  2¹²·3¹⁰ =

= 2²·2¹⁰·3¹⁰=

= 4·6¹⁰

Answer 2

$\left[2^0+2^1+3^{14}:\left(3\times 13^{12}\right)\right]^{12}:3^2=\\ \\ =\left(2^0+2^1+3^{14}:13^{13}\right)^{12}:3^2\\ \\ = \left(2^0+2^1+3\right)^{12}:3^2\\ \\ = \left(1+2+3\right)^{12}:3^2\\ \\ =6^{12}:3^2\\ \\ = 2^{12}\cdot 3^{12}:3^2\\ \\ =2^{12}\cdot 3^{10}\\\\ =2^2\cdot (2\cdot 3)^{10}\\ \\ = 4\cdot 6^{10}$