Question

(×^2+×+1)^2+(×^2-×+1)^2+(×^2-×-1)^2=​

Answer 1

Răspuns:(2²+x+1)²+(x²-x+1)²+(x²-x-1)²=

       4x∧4+x²+1+4x³+4x²+2x+x∧4+x²+1-2x³+2x²-2x+x∧4+x²+1-2x²-2x²+2x

       elimina numerelr opuse +2x si -2x; -2x² si +2x²;

4x∧4+x²+1+4x³+4x²+x∧4+x²+1-2x³+x∧4+x²+1-2x³+2x

redu termenii asemenea

6x∧4+7x²+1+4x³+1-2x³+1-2x³+2x

calculeaza suma numerelor pozitive

6x∧4+7x²+3+4x³-2x³-2x³+2x

redu termenii asemenea

6x∧4+7x²+2x+3

∧4 - inseamna la puterea a patra

Explicație pas cu pas: