Question

(2/×+1-4×/×la puterea 2-1-3×+6/×la puterea2+×-2):1/1-×=5

Answer 1

[2/(x+1)-4/(x²-1)-(3x+6)/(x²+x-2)]:1/((1-x)=5
[2/(x+1)-4/(x+1)(x-1)-(3x+6)/(x-1)(x+2)]·(1-x)=5
{[2(x-1)(x+2)-4(x+2)-(3x+6)(x+1)]/(x-1)(x+1)(x+2)}·(-1)(x-1)=5    simplificam cu x-1
-[(2x²+4x-2x-4-4x-8-3x²-3x-6x-6)/(x+1)(x+2)]=5
-(-x²-11x-18)=5(x+1)(x+2)
x²+11x+18=5x²+10x+5x+10
x²+11x+18=5x²+15x+10
x²-5x²+11x-15x+18-10=0
-4x²-4x+8=0                :(-4)
x²+x-2=0
Δ=1+8=9
x1=(-1+3)/2=2/2=1
x2=(-1-3)/2=-4/2=-2
S={-2,1}