Question

(√2+1)la a doua minus (√2-1)la a doua

Answer 1

Salut! ⚛  

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$(\sqrt{2}+1)^2 - (\sqrt{2}-1)^2$

Folosim formula (a - b)^2 = a^2 - 2ab + b^2:

$2+2\sqrt{2} + 1 - (2-2\sqrt{2}+1)$

$2 + 2\sqrt{2}+1-3+2\sqrt{2}$

$0+2\sqrt2 + 2\sqrt2 = \boxed{4\sqrt2}$

Raspuns final: $\boxed{4\sqrt2}$

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Luke48