Question

(√2+1)la patrat-2(√3-1)(√3+1)-(2√2-3)la patrat va rog

Answer 1

$( \sqrt{2} +1)^2-2( \sqrt{3} -1)( \sqrt{3} +1)-(2 \sqrt{2} -3)^2= \\ = \sqrt{2} ^2+2 \cdot \sqrt{2} \cdot 1+1^2-2(3-1)-[(2 \sqrt{2} )^2-2 \cdot 2 \sqrt{2} \cdot 3+3^2]= \\ =2+2 \sqrt{2} +1-2 \cdot 2-(8-12 \sqrt{2} +9)= \\ =2+2 \sqrt{2} +1-4-8+12 \sqrt{2} -9=14 \sqrt{2} -18$