Question

(2^10-2^9)*(2^9-2^8)*(2^8-2^7):2^24

Answer 1

$( {2}^{10} - {2}^{9} )( {2}^{9} - {2}^{8} )( {2}^{8} - {2}^{7} ) \div {2}^{24}$

$=\left\{ [ {2}^{9} (2 - 1)][ {2}^{8} (2 - 1)] [ {2}^{7} (2 - 1)] \right\}\div {2}^{24}$

$=( {2}^{9} \times {2}^{8} \times {2}^{7} ) \div {2}^{24}$

$= {2}^{9 + 8 + 7} \div {2}^{24}$

$= {2}^{24} \div {2}^{24}$

$= 1$