Question

[(2^10)^8+6^5*3^7+2^3^2]÷[(2^5)^16+6^12÷2^4+2^9] URGENT!!!!!! (dau coroana)​

Answer 1

Răspuns:

[(2^10)^8+6^5×3^7+2^9]÷[(2^5)16+6^12:2^7+2^9] =

=  (2⁸⁰ +6⁵*3⁷+2⁹)÷ (2⁸⁰+6¹²÷2⁷+2⁹)= (2⁸⁰ +6⁵*3⁵*3²+2⁹)÷ (2⁸⁰+6¹²÷2⁷+2⁹)=

= (2⁸⁰ +6⁵*3⁷+2⁹)÷ (2⁸⁰+2¹²*3¹²÷2⁷+2⁹)=(2⁸⁰ +6⁵*3⁷+2⁹)÷ (2⁸⁰+2⁵*3¹²+2⁹)=

=(2⁸⁰ +6⁵*3⁷+2⁹)÷ (2⁸⁰+2⁵*3⁵*3⁷+2⁹)=(2⁸⁰ +6⁵*3⁷+2⁹)÷ (2⁸⁰+6⁵*3⁷+2⁹)= 1

Explicație pas cu pas: