Question

2^100:[2^50•2^48+(2^10•2^15)^5:2^27+(5^76:5^75-3)^90•2^8+2^98]=?
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Answer 1

2^100:[2^50•2^48+(2^10•2^15)^5:2^27+(5^76:5^75-3)^90•2^8+2^98]=
=2^100:[2^98+(2^25)^5:2^27+(5^1-3)^90•2^8+2^98]=
=2^100:(2^98+2^125:2^27+2^90•2^8+2^98)=
=2^100:(2^98+2^98+2^98+2^98)=
=2^100:2^98×(2^0+2^0+2^0+2^0)=
=2^100:2^98×(1+1+1+1)=
=2^100:2^98×4=
=2^100:2^98×2^2=
=2^100:2^100=1