Question

2^100-[2^50*2^48+(2^10*2^15)^5:2^27+(5^76:5&%-3)^9*2^8+2^98]= 2^100-[2^98+(2^25)^5:2^27+(5-3)^90*2^8+2^98=2^100-(2^98+2^125:2^27+2^90*2^8+2^98)=2^100-(2^98+2^98+2^98+2^98)= va rog frumos daca stie cineva cum trebuie facut in continuare

Answer 1

2^100-2^98(1+1+1+1)=
2^100-2^98×4=
2^100-2^98×2^2
2^100-2^(98+2)=
2^100-2^100=0