Question

2^105-2^104-2^103-2^102

Answer 1

 [tex]2^{105}-2^{104}-2^{103}-2^{102}=\;\;\;\;\;\;\;(d\u{a}m\;factor\;comun\;pe\;2^{102}...)\\ =2^{102}\cdot(2^3-2^2-2^1-2^o)=2^{102}\cdot(8-4-2-1)=2^{102}\;\surd\surd[/tex]