Question

2^12:2^10+5^2-3^2+2018^0=?
Repede va roog

Answer 1

2^12:2^10=2^2=2×2=4

5^2=5×5=25

3^2=3×3=9

2018^0=1


4+25-9+1=
29-9+1=
20+1=
21










Succes in noul an școlar!

Answer 2

${2}^{12} \div {2}^{10} + {5}^{2} - {3}^{2} + {2018}^{0} \\ = {2}^{2} + 25 - 9 + 1 \\ = 4 + 25 - 9 + 1 \\ = 21.$