Question

2•[15²-3²•(x-5)]+2⁴•3²=324 Aflati-l pe x prin metoda mersului invers

Answer 1

2•[15²-3²•(x-5)]+2⁴•3²=324

2•[225-9•(x-5)]+16•9 = 324

2•[225-9•(x-5)]+144 = 324

2•[225-9•(x-5)] = 324 - 144

2•[225-9•(x-5)] = 180

225-9•(x-5) = 180 : 2

225-9•(x-5) = 90

9•(x-5) = 225 - 90

9•(x-5) = 135

x-5 = 135 : 9

x-5 = 15

x = 15+5

x = 20
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