Question

[ 2^16 × 2^18 : (2^15)^2 - 3^6 : (3^2)^2] × 7^18 × 17^0 : (7^8 × 7^9) - 3^2=?? (^ înseamnă puterea)​

Answer 1

Explicație pas cu pas:

$[ 2^{16} *2^{18} : {2^{15}} ^{2} - 3^6 : (3^2)^2]*7^{18}*17^0 : (7^8*7^9) - 3^2=[2^{16+18} :2^{30} -3^{6} :3^{4} ]*7^{18+0} :7^{8+9} -3^{2} = [2^{34-30} -3^{6-4} ]*7^{18-17} -3^{2} =[2^{4} -3^{2} ]*7-3^{2} =[16-9]*7-9=5*7-9=35-9=26$