Question

2+2×{2+2×[2+2×(2-2×a)]}=22

Answer 1

[tex]2+2\cdot\{2+2\cdot[2+2\cdot(2-2\cdot a)]\}=22\\ 2\cdot\{2+2\cdot[2+2\cdot(2-2\cdot a)]\}=22-2=20\\ 2+2\cdot[2+2\cdot(2-2\cdot a)]=20:2=10\\ 2\cdot[2+2\cdot(2-2\cdot a)]=10-2=8\\ 2+2\cdot(2-2\cdot a)=8:2=4\\ 2\cdot(2-2\cdot a)=4:2=2\\ 2-2\cdot a=2:2\\ 2-2\cdot a=1\\ -2\cdot a=1-2=-1\\ a=\frac{1}{2}[/tex]

Answer 2

2+2×{2+2×[2+2×(2-2×a)]}=22

2×{2+2×[2+2×(2-2×a)]}=22-2

2×{2+2×[2+2×(2-2×a)]}=20

2+2×[2+2×(2-2×a)]=20:2

2+2×[2+2×(2-2×a)]=10

2×[2+2×(2-2×a)] = 10-2

2×[2+2×(2-2×a)] = 8

2+2×(2-2×a) = 8:2

2+2×(2-2×a) = 4

2×(2-2×a) = 4-2

2×(2-2×a) = 2

2-2×a= 2:2

2-2×a = 1

2×a = 2-1

2×a = 1

a = 1/2