Question

            2          2
4(3√3-1)-5(√3-4)-√768
3(2√2+1)totul la puterea a 2+2(√2-3)la puterea a 2-(8-√7)(8+√7)
6(√2+3)la puterea a 2+4(3√2-1)la puterea 2-√288

Answer 1

4(3√3-1)-5(√3-4)-√768=
=12√3-4-5√3+20-16√3=
=-9√3+16

3(2√2+1)²+2(√2-3)²-(8-√7)(8+√7)=
=3(8+4√2+1)+2(2-6√2+9)-(64-7)=
=3(9+4√2)+2(11-6√2)-57=
=27+12√2+22-12√2-57=
=27+22-57= -8

6(√2+3)²+4(3√2-1)²-√288=
=6(2+6√2+9)+4(18-6√2+1)-12√2=
=6(11+6√2)+4(19-6√2)-12√2=
=66+36√2+76-24√2-12√2=
=142