Question

2,2 g substanta organica necunoscuta,x, cu masa molara 44 formeaza prin ardere 6,6g CO2 si 3,6 g H2O.
a)Determina formulele procentuala,bruta si moleculara ale substantei x
b)scrie formula de structura a substantei x
c)scrie ecuatia reactiei chimice de ardere a substantei x
Multumesc anticipat! Urgent!

Answer 1

s.o=2.2
M=44g/mol
a=6.6g CO2
b=3.6g H2O
%C=300a/11s=300*6.6/11*2.2=1980/24.2=81.81
%H=100b/9s=100*3.6/9*2.2=360/19.8=18.18
nC=%C*M/AC*100=81.81*44/12*100=3599.64/1200=3
nH=%H*M/AH*100=18.18*44/1*100=799.92/100=8.
Formula moleculara este C3H8 (propanul)
CH3-CH2-CH3
c) C3H8 + 5O2 => 3CO2 + 4H2O