Question

2,2 grame substanta organica X, cu masa molara = 44 formeaza prin ardere 6,6 grame CO2 și 3,6 grame H2O.
Se cere:
a) Formula moleculara a substantei X

Answer 1

n=m/M=2,2/44=0,05 moli s.o X

44g CO2.........................12g C
6,6g CO2........................x=1,8g C

18g H2O.........................2g H
3,6g H2O.......................x=0,4g H

n=m/M=1,8/12=0,15 moli C

n=m/M=0,4/2=0,2 moli H2

0,05 moli s.o X.........0,15 moli C......0,2 moli H2
1 mol.......................x=3 atomi C.......y=8 atomi H2

F.M => C3H8 -> n-propan