Question

(2+√2)la a doua-(2√2-3)la a doua

Answer 1

Metoda1 :=(2+rad2-2rad2+3)(2+rad2+2rad2-3)=(5-rad2)(3rad2  -  1)= 15rad2 - 5 - 3x2 + rad2 = 16rad2 - 11, am folosit a^2 - b^2 = (a-b)(a+b)
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Metoda2: 4+4rad2 + 2 - 8+ 12rad2 -9 = 16rad2  -  11, am folosit (a+/-b)^2 = a^2 +/- 2ab +b^2
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Succes in continuare!