Question

2 ^ 2000 ÷[(25^50÷5^99-3^51÷9^25)^1999+(2^111)^18+2×2^1997] va rog e urgent

Answer 1

Răspuns

Explicație pas cu pas:

2^2000 ÷[(25^50÷5^99-3^51÷9^25)^1999+(2^111)^18+2×2^1997] =

=2^2000 ÷[(5^100÷5^99-3^51÷3^50)^1999+2^1998+2^1998] =

=2^2000 ÷[(5-3)^1999+2^1998(1+1)] =

=2^2000 ÷(2^1999+2^1998*2) =

=2^2000 ÷(2^1999+2^1999) =

=2^2000 ÷2^1999*(1+1) =

=2^2000 ÷2^1999*2 =

=2^2000 ÷2^2000 =2^0=1