Question

2√24·(3 supra √6 -√2 supra√3

Answer 1

       
$2 \sqrt{24}*( \frac{3}{ \sqrt{6}}- \frac{ \sqrt{2}}{ \sqrt{3}})= \\ \\ =2 \sqrt{4*6}*( \frac{3\sqrt{6}}{6}- \frac{ \sqrt{2}*\sqrt{3}}{3})= \\ \\ =2*2 \sqrt{6}*( \frac{\sqrt{6}}{2}- \frac{ \sqrt{6}}{3})= \\ \\= 4 \sqrt{6}*( \frac{3\sqrt{6}}{6}- \frac{ 2\sqrt{6}}{6})= \\ \\= 4 \sqrt{6}* \frac{\sqrt{6}}{6} = \\ \\= \frac{4 \sqrt{6}*\sqrt{6}}{6} = \frac{4*6}{6}=\boxed{4}$