Question

2^2a+1+2^3b+2^2c=112​

Answer 1

2^(2a+1) + 2^3b + 2^2c = 112

Dar 112 = 16 + 96 = 16 + 32 + 64 = 2^4 + 2^5 + 2^6 =>

2^(2a+1) = 2^5 => 2a+1 = 5 => 2a = 6 => a = 3

2^3b = 2^6 => 3b = 6 => b = 2

2^2c = 2^4 => 2c = 4 => c = 2