Question

2×3^2-81^10:27^5:[5^3-5×(4^2-11)^2+3^5]^5


125^5:25^7+3×[16^3×4^2:8^5+(7^5×3^4)^10:(7^2)^25:9^20]

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Answer 1

2×3^2-81^10:27^5:[5^3-5×(4^2-11)^2+3^5]^5 =

= 2×9-(3^4)^10:(3^3)^5:[125-5×(16-11)^2+243]^5=

= 18-3^40:3^15:(125-5×5^2+243)^5 =

= 18-3^25:(125-125+243)^5 =

= 18 - 3^25 : 243^5 =

= 18 - 3^25 : (3^5)^5 =

= 18 - 3^25 : 3^25 =

= 18 - 1 =

= 17

125^5:25^7+3×[16^3×4^2:8^5+(7^5×3^4)^10:(7^2)^25:9^20] =

= (5^3)^5:(5^2)^7×[(2^4)^3×(2^2)^2:(2^3)^5+(7^50×3^40):7^50 : (3^2)^20] =

= 5^15:5^14×(2^12×2^4:2^15+3^40:3^40)=

= 5 × (2^16 : 2^15 + 1) =

= 5 × (2 + 1) =

= 5 × 3 =

= 15