Question

(2-√3)³=.....va rog ajutatima

Answer 1

$\it (a-b)^3 = a^3-3a^2b+3ab^2-b^3$

$\it (2-\sqrt3)^3 = 2^3-3\cdot2^2\sqrt3+3\cdot2\cdot(\sqrt3)^2 -(\sqrt3)^3$

$\it = 8-12\sqrt3+18-3 \sqrt3 = 26 - 15\sqrt3 .$