Question

[2+(3×5-2×x)]÷3+3÷[2+(49÷7-2)÷5]=6

x=1


REPEDE!!!

Answer 1

Răspuns:

Explicație pas cu pas:

[2+(3*5-2/x)]÷3+3÷[2+(49÷7-2)÷5]=6

[2+(15-2x)]÷3+3÷[2+(7-2)÷5]=6

[2+(15-2x)]÷3+3÷(2+5÷5)=6

[2+(15-2x)÷3+3÷(2+1)=6

[2+(15-2x)]÷3+3÷3=6

[2+(15-2x)]÷3+1=6

[2+(15-2x)]÷3=6-1

[2+(15-2x)]=5*3

[2+(15-2x)]=15

(15-2x)=15-2

15-15+2=2x

2x=2

x=2/2

x=1