Question

2 ,3 si 4 prin metoda mersului invers

Answer 1

1.a) (a+5):6=11
a+5=11×6
a+5=66
a=66-5
a=61

b) (a-6):5=11
a-6=11×5
a-6=55
a=55+6
a=61

2.2018:(a×5+4)=2
a×5+4=2018:2
a×5+4=1009
a×5=1009-4
a×5=1005
a=1005:5
a=201
3.(a:2):2=16
a:2=16×2
a:2=32
a=32×2
a=64