Question

2,3 si 4 Va rog ! Dau coroana la toti !!

Answer 1

2) a. t5 = timpul de stationare

t5= t3- t2= 10 h 30 min 40 s - 10 h 25 min = 5 min 40 sec

   b. t6=timpul miscarii de la prima la a doua statie

t6=t4-t1-t5= 12 h 30 min 55 sec -8h 15 min 20 s- 5 min 40 sec (pt ca in timpul asta a stationat) = 4 h 6 min 55 sec

3) (t) si= s ( secunda este unitatea de masura in sistem international pentru timp )

     1min=60 sec ; 1h= 3600 sec ; 1 zi= 86.400 sec

t=  9 zile 8 ore 16 min

t= 9*86.400 + 8* 3600 + 60*16

t=777.600 + 28.800 + 960= 807.360 s

4) 0.3 min

  1 min= 60 sec

0.3 min= 60*0.3=18 sec