Question

(-2)^3 x 4 comparat cu (-3)^10 x 9^8 :(-27)^7 Dau coroana

Answer 1

$(-2)³\cdot4 \: □ \: (-3)¹⁰\cdot 9⁸:(-27)⁷ \\ -2³\cdot2²\: □\: 3¹⁰\cdot(3²)⁸:(-3³)⁷ \\ -2⁵\:□\: 3²⁶:(-3)²¹ \\ -2⁵\cdot3⁵ \\ \boxed{-32 < 243}$

Answer 2

Explicație pas cu pas:

${( - 2)}^{3} \cdot 4 = - {2}^{3} \cdot {2}^{2} = - {2}^{5}$

${( - 3)}^{10} \cdot {9}^{8} : {( - 27)}^{7} = {3}^{10} \cdot {( {3}^{2} )}^{8} : ( - {( {3}^{3})}^{7}) = - {3}^{10} \cdot {3}^{16} : {3}^{21} = - {3}^{10 + 16 - 21} = - {3}^{5}$

$- {2}^{5} > - {3}^{5} \implies \\ \bf {( - 2)}^{3} \cdot 4 > {( - 3)}^{10} \cdot {9}^{8} : {( - 27)}^{7}$